If 1=11, 2=22, 3=33, 4=44, 5=55, 6=66, 7=77, then 11=?

the answer is 112

my explanation: 1=(the number =1)+summation(1)=11 ,test 1*2=2 sum of 11=2 ;

2 =(the number =2)+summation(2)=22 ,test 2*2=4 sum of 22=4 ;

3 =(the number =3)+summation(3)=33 ,test 3*2=6 sum of 33=6 ;

4 =(the number =4)+summation(4)=44 ,test 4*2=8 sum of 44=8 ;

5 =(the number =5)+summation(5)=55 ,test 5*2=10 sum of 55=10 ;

6 =(the number =6)+summation(6)=66 ,test 6*2=12 sum of 66=12 ;

7 =(the number =7)+summation(7)=77 ,test 7*2=14 sum of 77=14 ;

….

10=(the number =10)+summation(1)=101 ,test (1+0)*2=2 sum of 101=2

11=(the number =11)+summation(2)=112 ,test (1+1)*2=4 sum of 112=4

second demonstration:

1=11, 2=22 ,3=33, 4=44, 5=55…..10=101, 11=112

from 1=11 to 9=99 are 9 numbers =+11 THAT IS

11+11=22, 22+11=33, 33+11=44….

from 9=99 to 10=101 is 1 number=+2 THAT IS 99+2=101

from 10=101 to 18=189 are always 9 numbers=+11

In conclusion sequence is repeating cycle :

the first nine numbers(+11) then tenth number(+2)

the second nine numbers(+11) then tenth number(+2)

the third nine numbers(+11) then tenth number(+2)