If f(1) = 160 and f(n + 1) = –2f(n), what is f(4)?
If f(1) = 160 and f(n + 1) = –2f(n), what is f(4)? Risposta: #f(4)=-1280# Spiegazione: As #f(1)=160# e #f(n+1)=–2f(n)# #f(2)=-2f(1)=-2xx160=-320# #f(3)=-2f(2)=-2xx(-320)=640# #f(4)=-2f(3)=-2xx640=-1280#