Come consideri # x ^ 2 + 8x + 12 #?
Come consideri # x ^ 2 + 8x + 12 #? Risposta: #x^2+8x+12=color(green)((x+2)(x+6))# Spiegazione: Generalmente #color(white)(“XXX”)(x^2+(color(red)(a)+color(blue)(b))x+color(red)(a)*color(blue)(b))=(x+color(red)(a))(x+color(blue)(b))# #8 = color(red)(2)+color(blue)(6)# e #12=color(red)(2)*color(blue)(6)# So #x^2+8x+12# #color(white)(“XXX”)=(x^2+(color(red)(2)+color(blue)(6))x+color(red)(2)*color(blue)(6)# #color(white)(“XXX”)=(x+color(red)(2))(x+color(blue)(6))#