Hildagarde

Come si converte r = sin (theta) in equazione rettangolare? Risposta: #x^2+(y-1/2)^2=1/4# Spiegazione: #”to convert from “color(blue)”polar to rectangular”# #•color(white)(x)r=sqrt(x^2+y^2)# #•color(white)(x)y=rsinthetarArrsintheta=y/r# #r=sintheta# #r=y/rlarr”multiply both sides by “r# #r^2=y# #x^2+y^2-y=0larrcolor(blue)”rectangular equation”# #”which is the equation of a circle”# #x^2+(y-1/2)^2=1/4# #”centre “=(0,1/2)” and radius “=1/2# graph{(x^2+(y-1/2)^2-1/4)=0 [-10, 10, -5, 5]}