Il valore di (cos (pi / 12) -sin (pi / 12)) (tan (pi / 12) + cos (pi / 12)) ??
Il valore di (cos (pi / 12) -sin (pi / 12)) (tan (pi / 12) + cos (pi / 12)) ?? (cos (pi/12)-sin (pi/12))(tan (pi/12)+cos( pi/12) ) = (cos (pi/12)/cos (pi/12)-sin (pi/12)/cos (pi/12))cos (pi/12)(tan (pi/12)+cos( pi/12) ) =(1-tan(pi/12))(sin(pi/12)+cos^2(pi/12)) =(1-tan(pi/12))(sin(pi/12)+1/2(1+cos(pi/6)) =(1-tan(pi/12))(sin(pi/12)+1/2(1+cos(pi/6)) Adesso tan(pi/12)=tan(pi/3-pi/4) =(tan(pi/3)-tan(pi/4))/(1+tan(pi/3)tan(pi/4))=(sqrt3-1)/(sqrt3+1) Di nuovo sin(pi/12) =sin(pi/3-pi/4) =sin(pi/3)cos(pi/4)-cos(pi/3)sin(pi/4) =(sqrt3-1)/(2sqrt2) So (1-tan(pi/12))(sin(pi/12)+1/2(1+cos(pi/6)) =(1-(sqrt3-1)/(sqrt3+1))((sqrt3-1)/(2sqrt2)+1/2(1+sqrt3/2)) … Leggi tutto