Sonnnie – GufoSaggio

Come risolvi $S = 2 π r h + 2 π r^{2}$ $S = 2pirh + 2pir ^ 2$ per $h$ $h$ ?

Dicembre 20, 2019

Come risolvi $S = 2 π r h + 2 π r^{2}$ $S = 2pirh + 2pir ^ 2$ per $h$ $h$ ? Risposta: $h = \frac{S - 2 π r^{2}}{2 π r}$ $h=(S-2pir^2)/(2pir)$ Spiegazione: $”isolate the term containing h”$ $rArr2pirh=S-2pir^2$ $”divide both sides by “2pir$ $(cancel(2pir) h)/cancel(2pir)=(S-2pir^2)/(2pir)$ $rArrh=(S-2pir^2)/(2pir)$