Come si semplifica #cos x + sin x tan x #?
Come si semplifica #cos x + sin x tan x #? Risposta: #secx# Spiegazione: #”using the “color(blue)”trigonometric identities”# #•color(white)(x)tanx=sinx/cosx” and “secx=1/cosx# #•color(white)(x)sin^2x+cos^2x=1# #rArrcosx+sinx xx sinx/cosx# #=cos^2x/cosx+sin^2x/cosx# #=(cos^2x+sin^2x)/cosx=1/cosx=secx#