How do you solve $2 x + 3 = 3 x - 4$ $2x+3=3x-4$ ?

Risposta:

With practice you can do these quicker as you learn the shortcut.

$x = 7$ $x=7$

Spiegazione:

Objective is to have a single $x$ $x$ on one side of the = and everything else on the other side.

Dato: $2 x + 3 = 3 x - 4$ $" "color(green)(2x+3=3x-4)$

'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

$Step 1 Having all the x terms on one side of =$ $color(blue)("Step 1 ")color(brown)("Having all the "x" terms on one side of =")$

Sottrarre $2 x$ $color(red)(2x)$ da entrambi i lati

$2 x - 2 x + 3 = 3 x - 2 x - 4$ $color(green)(2xcolor(red)(-2x)+3=3xcolor(red)(-2x)-4)$

$0 + 3 = x - 4$ $0+3=x-4$

Swap round

$x - 4 = 3$ $x-4=3$
'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
$Step 2 Have just x on the left of =$ $color(blue)("Step 2 ")color(brown)("Have just "x" on the left of =")$

aggiungere $4$ $color(red)(4)$ da entrambi i lati

$x - 4 + 4 = 3 + 4$ $color(green)(x-4color(red)(+4)=3color(red)(+4))$

$x = 7$ $x=7$

How do you solve 2x+3=3x−42x+3=3x-4?

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How do you solve $2 x + 3 = 3 x - 4$ $2x+3=3x-4$ ?