Come risolvi y = 2 log (x) y=2log(x)?
Risposta:
x=sqrt(10^y)x=√10y
Spiegazione:
y= 2log x or y= log x^2; [log x^m=mlogx]y=2logxory=logx2;[logxm=mlogx]
:. x^2=10^y :. x=sqrt(10^y );
[log _b (N)=x , poi b^x=N]
[Ans]
x=sqrt(10^y)x=√10y
y= 2log x or y= log x^2; [log x^m=mlogx]y=2logxory=logx2;[logxm=mlogx]
:. x^2=10^y :. x=sqrt(10^y );
[log _b (N)=x , poi b^x=N]
[Ans]