Denny

Come si integra #sqrt (1-x ^ 2) #?



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Come si integra #sqrt (1-x ^ 2) #? Risposta: La risposta è #=1/2arcsinx+1/2xsqrt(1-x^2)+C# Spiegazione: lasciare #x=sintheta#, #=>#, #dx=costhetad theta# #costheta=sqrt(1-x^2)# #sin2theta=2sinthetacostheta=2xsqrt(1-x^2)# Pertanto, l'integrale è #I=intsqrt(1-x^2)dx=intcostheta*costheta d theta# #=intcos^2thetad theta# #cos2theta=2cos^2theta-1# #cos^2theta=(1+cos2theta)/2# Perciò, #I=1/2int(1+cos2theta)d theta# #=1/2(theta+1/2sin2theta)# #=1/2arcsinx+1/2xsqrt(1-x^2)+C#

What is the Plum Pudding Model?



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What is the Plum Pudding Model? Risposta: It is the model of the atom proposed by J. J. Thomson where inside a uniform “ball” of positive charge are located small “plums” of negatively charged electrons. Spiegazione: Thomson knew about the existence of the electrons (he measured some of their properties) but didn’t know a lot … Leggi tutto