How are there #pi# bonds in #B_2# molecule without #sigma# bonds?
How are there #pi# bonds in #B_2# molecule without #sigma# bonds? There shouldn’t be, and that’s why #”B”_2# is very unstable; it has two orthogonally-localized half-#pi# bonds, which is quite a weak bond. Imagine that each #”B”# takes the place of a #”CH”# on #”HC”-=”CH”#. Then, take away the #sigma# bond, the two #”H”# atoms, … Leggi tutto