Marika

Riscrivi # sin ^ 4 (x) tan ^ 2 (x) # in termini di primo potere del coseno? Risposta: #=> (1-3cos^2(x) +3cos^4(x) -cos^6(x))/cos^2(x)# Spiegazione: #sin^4(x)tan^2(x)# #=> (1-cos^2(x))^2(sin^2(x))/cos^2(x)# #=> (1-2cos^2(x) + cos^4(x))(sin^2(x))/cos^2(x)# #=>( sin^2(x)-2sin^2(x)cos^2(x) + sin^2(x)cos^4(x))/cos^2(x)# #=> ((1-cos^2(x)) -2(1-cos^2(x))cos^2(x)+(1-cos^2(x))cos^4(x))/cos^2(x)# #=> (1-cos^2(x) -2cos^2(x)+2cos^4(x)+cos^4(x)-cos^6(x))/cos^2(x)# #=> (1-3cos^2(x) +3cos^4(x) -cos^6(x))/cos^2(x)#