Come consideri x ^ 2- 6x + 8 ?

Come consideri x ^ 2- 6x + 8 ? Risposta: (x-2)(x-4) Spiegazione: ”consider the factors of + 8 which sum to give the” ”coefficient of the x-term, that is – 6″ ”the factors of + 8 which sum to – 6 are – 4 and – 2″ rArrx^2-6x+8=(x-4)(x-2)