Come consideri # x ^ 2- 6x + 8 #?

Come consideri # x ^ 2- 6x + 8 #? Risposta: #(x-2)(x-4)# Spiegazione: #”consider the factors of + 8 which sum to give the”# #”coefficient of the x-term, that is – 6″# #”the factors of + 8 which sum to – 6 are – 4 and – 2″# #rArrx^2-6x+8=(x-4)(x-2)#