Come risolvi per x in #ax = bx -c #?
Come risolvi per x in #ax = bx -c #? Risposta: #x=-c/(a-b)# Spiegazione: #”Collect terms in x on the left side “# #”subtract “bx” from both sides”# #ax-bx=-c# #”take out a “color(blue)”common factor “x# #x(a-b)=-c# #”divide both sides by “a-b# #x=-c/(a-b)#