Why does lna–lnb=ln(ab)?
Why does lna–lnb=ln(ab)? It does not matter what base we use providing the same base is used for all logarithms, here we are using bease e. Cerchiamo di definire A,B.C as follows=: A=lna⇔a=eA, # B = ln b iff b = e^B … Leggi tutto