Come risolvi # 4x ^ 2 = 81 #?
Risposta:
x = ±#9/2 #
Spiegazione:
#" isolate the " x^2 " term , by dividing by 4 "#
hence # x^2 = 81/4 #
#rArr x = ± sqrt(81/4) = ± 9/2 #
x = ±#9/2 #
#" isolate the " x^2 " term , by dividing by 4 "#
hence # x^2 = 81/4 #
#rArr x = ± sqrt(81/4) = ± 9/2 #