Come risolvi $4x ^ 2 = 81$ ?

x = ± $9/2$

$" isolate the " x^2 " term , by dividing by 4 "$

hence $x^2 = 81/4$

$rArr x = ± sqrt(81/4) = ± 9/2$

Come risolvi 4x ^ 2 = 81 4x ^ 2 = 81 ?