Come risolvi per x in #ax = bx -c #?
Risposta:
#x=-c/(a-b)#
Spiegazione:
#"Collect terms in x on the left side "#
#"subtract "bx" from both sides"#
#ax-bx=-c#
#"take out a "color(blue)"common factor "x#
#x(a-b)=-c#
#"divide both sides by "a-b#
#x=-c/(a-b)#