Dicembre 20, 2019

di Sonnnie

Come risolvi $S = 2 π r h + 2 π r^{2}$ $S = 2pirh + 2pir ^ 2$ per $h$ $h$ ?

Risposta:

$h = \frac{S - 2 π r^{2}}{2 π r}$ $h=(S-2pir^2)/(2pir)$

Spiegazione:

$isolate the term containing h$ $"isolate the term containing h"$

$\Rightarrow 2 π r h = S - 2 π r^{2}$ $rArr2pirh=S-2pir^2$

$divide both sides by 2 π r$ $"divide both sides by "2pir$

$\frac{2 π r h}{2 π r} = \frac{S - 2 π r^{2}}{2 π r}$ $(cancel(2pir) h)/cancel(2pir)=(S-2pir^2)/(2pir)$

$\Rightarrow h = \frac{S - 2 π r^{2}}{2 π r}$ $rArrh=(S-2pir^2)/(2pir)$

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