Come si converte r = sin (theta) in equazione rettangolare?
Risposta:
#x^2+(y-1/2)^2=1/4#
Spiegazione:
#"to convert from "color(blue)"polar to rectangular"#
#•color(white)(x)r=sqrt(x^2+y^2)#
#•color(white)(x)y=rsinthetarArrsintheta=y/r#
#r=sintheta#
#r=y/rlarr"multiply both sides by "r#
#r^2=y#
#x^2+y^2-y=0larrcolor(blue)"rectangular equation"#
#"which is the equation of a circle"#
#x^2+(y-1/2)^2=1/4#
#"centre "=(0,1/2)" and radius "=1/2#
graph{(x^2+(y-1/2)^2-1/4)=0 [-10, 10, -5, 5]}