Come si semplifica $2^{\frac{5}{2}} - 2^{\frac{3}{2}}$ $2 ^ (5/2) - 2 ^ (3/2)$ ?

Generalmente
$b^{p + q} = b^{p} \cdot b^{q}$ $b^(p+q) = b^p*b^q$

so
$2^{\frac{5}{2}}$ $2^(5/2)$ può essere riscritto come $2^{\frac{3}{2}} \cdot 2^{\frac{2}{2}} = 2^{\frac{3}{2}} \cdot 2$ $2^(3/2)*2^(2/2) = 2^(3/2)*2$

$2^{\frac{5}{2}} - 2^{\frac{3}{2}}$ $2^(5/2)-2^(3/2)$

$= 2^{\frac{3}{2}} (2 - 1)$ $= 2^(3/2)(2-1)$

e da allora
$2^{\frac{3}{2}} = {(2^{3})}^{\frac{1}{2}} = 2 \sqrt{2}$ $2^(3/2) = (2^3)^(1/2) = 2sqrt(2)$

$2^{\frac{5}{2}} - 2^{\frac{3}{2}} = 2 \sqrt{2}$ $2^(5/2)-2^(3/2) = 2sqrt(2)$

Come si semplifica 2 ^ (5/2) - 2 ^ (3/2) 252−232 2 ^ (5/2) - 2 ^ (3/2) ?

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Come si semplifica $2^{\frac{5}{2}} - 2^{\frac{3}{2}}$ $2 ^ (5/2) - 2 ^ (3/2)$ ?