Come si semplifica # 4/8 #?
#4/8 = (4 xx 1)/(4 xx 2) = (color(red)(cancel(color(black)(4))) xx 1)/(color(red)(cancel(color(black)(4))) xx 2) = 1/2#
#4/8 = (4 xx 1)/(4 xx 2) = (color(red)(cancel(color(black)(4))) xx 1)/(color(red)(cancel(color(black)(4))) xx 2) = 1/2#