Come trovi # (fg) (4) # dato #f (x) = 4x-3 # e #g (x) = x ^ 3 + 2x #?
Risposta:
#(f-g)(4)=-59#
Spiegazione:
#" obtain " (f-g)=f(x)-g(x)#
#f(x)-g(x)=4x-3-x^3-2x#
#color(white)(f(x)-g(x))=2x-3-x^3#
#"to evaluate " (f-g)(4)" substitute x = 4 into " (f-g)#
#(f-g)(color(red)(4))=(2xxcolor(red)(4))-3-(color(red)(4))^3#
#color(white)((f-g)(4))=8-3-64#
#color(white)((f-g)(4))=-59#