Come valuti # 2x ^ {2} + 3x = 5 #?
Risposta:
#(x-1)(2x+5)=0#
Spiegazione:
#"rearrange equation into standard form"#
#rArr2x^2+3x-5=0larrcolor(blue)"in standard form"#
#"factor the quadratic using the a-c method"#
#"the factors of - 10 which sum to + 3 are + 5 and - 2"#
#2x^2-2x+5x-5=0larrcolor(blue)"split the middle term"#
#color(red)(2x)(x-1)color(red)(+5)(x-1)=0larrcolor(blue)"factor by grouping"#
#"take out a common factor "(x-1)#
#(x-1)(color(red)(2x+5))=0larrcolor(blue)"factored form"#