Elemental S reacts with O2 to form SO3 according to the reaction
2S+3O2→2SO3
Part A: How many O2 molecules are needed to react with 6.67 g of S?
Express your answer numerically in units of molecules.
Risposta:
Guarda il stechiometria...S(s)+32O2(g)→SO3(g)
Spiegazione:
The stoichiometric coefficients are in terms of moles, and certainly this REPRESENTS a numerical quantity....i.e. where NA=Avogadro's number=6.022×1023⋅mol−1.
With respect to sulfur we got a molar quantity of...
6.67⋅g32.0⋅g⋅mol−1=0.208⋅mol
And therefore CLEARLY we need 0.208⋅mol×32=0.313⋅mol OF OXYGEN MOLECULES for stoichiometric equivalence.
0.208⋅mol×32×6.022×1023⋅mol−1=1.88×1023⋅oxygen molecules.
And we use la Talpa here precisely as would the dozen, O l' gross, as we would any other collective number...
And the mass of this quantity of oxygen is...?