Elemental S reacts with O2 to form SO3 according to the reaction
2S+3O2→2SO3

Part A: How many O2 molecules are needed to react with 6.67 g of S?
Express your answer numerically in units of molecules.

Risposta:

Guarda il stechiometria...S(s)+32O2(g)SO3(g)

Spiegazione:

The stoichiometric coefficients are in terms of moles, and certainly this REPRESENTS a numerical quantity....i.e. where NA=Avogadro's number=6.022×1023mol1.

With respect to sulfur we got a molar quantity of...

6.67g32.0gmol1=0.208mol

And therefore CLEARLY we need 0.208mol×32=0.313mol OF OXYGEN MOLECULES for stoichiometric equivalence.

0.208mol×32×6.022×1023mol1=1.88×1023oxygen molecules.

And we use la Talpa here precisely as would the dozen, O l' gross, as we would any other collective number...

And the mass of this quantity of oxygen is...?

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