Qual è la configurazione elettronica per # Fr #?
Risposta:
#[Rn]7s^1#
Spiegazione:
A partire dal la tavola periodica, #Z#, la numero atomico of #Fr=87#
E quindi,
#1s^(2)2s^(2)2p^(6)3s^(2)3p^(6)3d^(10)4s^(2)4p^(6)4d^(10)5s^(2)5p^(6)4f^(14)5d^(10)6s^(2)6p^(6)7s^1 #
Well, I have got 87 electrons there at least. Of course, all the action, all the chemistry takes place at #7s^1#, Cioè #Fr# is univalent and would react as an alkali metal. It is extremely rare element and gram quantities would be unknown.