Come trovi la derivata di # y = ln (5x) #?

#y'=1/x#

Spiegazione

Suppose, #y=ln(b(x))#

then using Chain Rule,

#y'=1/(b(x))*(b(x))'#

Similarly following for the above function yields,

#y'=1/(5x)*(5x)'#

#y'=1/(5x)*5#

#y'=1/x#