Come risolvi # 2x ^ 2 + 5x = 0 # usando la formula quadratica?

#ax^2+bx+c=0#

#2x^2+5x=0#

#a=2" ; "b=5" ; "c=0#

#Delta=sqrt(b^2-4*a*c)#

#Delta=sqrt(5^2-4*2*0)#

#Delta=sqrt 5^2#

#Delta=±5#

#x_("1,2")=(-b±Delta)/(2*a)#

#x_1=(-5-5)/(2*2)=-10/4=-5/2#

#x_2=(-5+5)/(2*2)=0#

#x={0,-5/2}#

#"Or simply"#

#2x^2+5x=0#

#2cancel(x^2)=-5cancel(x)#

#2x=-5#

#x=-5/2#