Come consideri # x ^ 2 + 8x + 12 #?
Risposta:
#x^2+8x+12=color(green)((x+2)(x+6))#
Spiegazione:
Generalmente
#color(white)("XXX")(x^2+(color(red)(a)+color(blue)(b))x+color(red)(a)*color(blue)(b))=(x+color(red)(a))(x+color(blue)(b))#
#8 = color(red)(2)+color(blue)(6)#
e
#12=color(red)(2)*color(blue)(6)#
So
#x^2+8x+12#
#color(white)("XXX")=(x^2+(color(red)(2)+color(blue)(6))x+color(red)(2)*color(blue)(6)#
#color(white)("XXX")=(x+color(red)(2))(x+color(blue)(6))#