Come risolvi `10 ^ {x} = 75`?

`"using the "color(blue)"law of logarithms"`

`•color(white)(x)logx^nhArrnlogx`

`"take log of both sides"`

`"note that "logx-=log_(10)x" and "log_(10)10=1`

`log10^x=log75`

`xlog10=log75`

`x=log75/log10=log75~~1.875`