Come risolvi # cosx = 1/2 #?
Risposta:
#x=pi/3" or "x=(5pi)/3#
Spiegazione:
#"since "cosx>0#
#"then x will be in the first/fourth quadrants"#
#cosx=1/2#
#rArrx=cos^-1(1/2)=pi/3larrcolor(blue)" angle in first quadrant"#
#"or "x=(2pi-pi/3)=(5pi)/3larrcolor(blue)" angle in fourth quadrant"#