Come si differenzia # 1 + cos ^ 2 (x) #?
Risposta:
#-sin2x#
Spiegazione:
#"differentiate using the "color(blue)"chain rule"#
#"given "y=f(g(x))" then"#
#dy/dx=f'(g(x))xxg'(x)larrcolor(blue)"chain rule"#
#y=1+(cosx)^2#
#dy/dx=2cosx xxd/dx(cosx)#
#color(white)(dy/dx)=-2sinxcosx=-sin2x#