Come si differenzia 1 + cos ^ 2 (x) ?

Risposta:

-sin2x

Spiegazione:

"differentiate using the "color(blue)"chain rule"

"given "y=f(g(x))" then"

dy/dx=f'(g(x))xxg'(x)larrcolor(blue)"chain rule"

y=1+(cosx)^2

dy/dx=2cosx xxd/dx(cosx)

color(white)(dy/dx)=-2sinxcosx=-sin2x

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