Come si verifica $sec x csc x = tan x + cot x$ $secxcscx = tanx + cotx$ ?

vedi sotto

$sec x csc x = tan x + cot x$ $secx csc x = tanx+cotx$

Lato destro : $= \frac{sin x}{cos x} + \frac{cos x}{sin x}$ $=sinx/cosx + cosx/sinx$

$= \frac{sin x sin x + cos x cos x}{cos x sin x}$ $=(sinx sinx + cosxcosx)/( cosx sinx)$

$= \frac{{sin}^{2} x + {cos}^{2} x}{cos x sin x}$ $=(sin^2x + cos^2x)/(cosx sinx)$

$= \frac{1}{cos x sin x}$ $=1/(cosx sinx)$

$= \frac{1}{cos x} \cdot \frac{1}{sin x}$ $=1/cos x *1/sinx$

$= sec x csc x$ $=secxcscx$

$:.=$ Lato sinistro

Come si verifica secxcscx = tanx + cotx secxcscx=tanx+cotx secxcscx = tanx + cotx ?