Come trovare b in forma di equazione lineare y = mx + b se le 2 coordinate sono (5,6) e (1,0)?

Risposta:

#color(blue)(y = (3/2)x - (3/2)#

#color(purple)( " is the slope-intercept form of equation with slope = 3/2, y-intercept = -3/2"#

Spiegazione:

https://www.onlinemathlearning.com/equation-of-a-line-types.html

#(x_1,y_1) = (5,6), (x_2,y_2) = (1,0)#

L'equazione della linea è #(y-y_1) / (y_2 - y_1) = (x-x_1) / (x_2-x_1) #

#(y - 6) / (0-6) = (x-5) / (1-5)#

#(y-6) /cancel( -6 )^color(red)(3)= (x-5) /cancel( -4)^color(red)(2)#

#2y - 12 = 3x - 15, " cross multiplying"#

#2y = 3x - 15 + 12#

Forma standard di pendenza-equcept equation is #color(indigo)(y = mx + c#
#color(blue)(y = (3/2)x - (3/2)#

#color(purple)( " is the slope-intercept form of equation with slope = 3/2, y-intercept = -3/2"#

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