Come valuta #cot ((5pi) / 6) #?
Risposta:
#cot((5pi)/6)=-sqrt3#
Spiegazione:
#cot((5pi)/6)#
= #cot(pi-pi/6)#
As #cot(pi-theta)=-cottheta#
#cot(pi-pi/6)=-cot(pi/6)=-sqrt3#
#cot((5pi)/6)=-sqrt3#
#cot((5pi)/6)#
= #cot(pi-pi/6)#
As #cot(pi-theta)=-cottheta#
#cot(pi-pi/6)=-cot(pi/6)=-sqrt3#