# What is the derivative of arcsin(2x)?

The derivative of this type of trigonometric function is given by the general rule that follows:

If y=arcsin(u), poi y'=(u')/(sqrt(1-u^2))

As in this case our u=2x, poi u'=2 and we can proceed 🙂

(dy)/(dx)=2/sqrt(1-(2x)^2)=1/sqrt(1-4x^2)