Come consideri # x ^ 2- 6x + 8 #?
Risposta:
#(x-2)(x-4)#
Spiegazione:
#"consider the factors of + 8 which sum to give the"#
#"coefficient of the x-term, that is - 6"##"the factors of + 8 which sum to - 6 are - 4 and - 2"#
#rArrx^2-6x+8=(x-4)(x-2)#