If f(1) = 160 and f(n + 1) = –2f(n), what is f(4)?
Risposta:
#f(4)=-1280#
Spiegazione:
As #f(1)=160# e #f(n+1)=–2f(n)#
#f(2)=-2f(1)=-2xx160=-320#
#f(3)=-2f(2)=-2xx(-320)=640#
#f(4)=-2f(3)=-2xx640=-1280#
#f(4)=-1280#
As #f(1)=160# e #f(n+1)=–2f(n)#
#f(2)=-2f(1)=-2xx160=-320#
#f(3)=-2f(2)=-2xx(-320)=640#
#f(4)=-2f(3)=-2xx640=-1280#