If f(1) = 160 and f(n + 1) = –2f(n), what is f(4)?
Risposta:
f(4)=-1280
Spiegazione:
As f(1)=160 e f(n+1)=–2f(n)
f(2)=-2f(1)=-2xx160=-320
f(3)=-2f(2)=-2xx(-320)=640
f(4)=-2f(3)=-2xx640=-1280
f(4)=-1280
As f(1)=160 e f(n+1)=–2f(n)
f(2)=-2f(1)=-2xx160=-320
f(3)=-2f(2)=-2xx(-320)=640
f(4)=-2f(3)=-2xx640=-1280