# What volume of 0.10 M NaOH can be prepared from 250 mL of 0.30 M NaOH?

"750 mL"

#### Spiegazione:

The thing to notice here is that the soluzione iniziale is 3 times more concentrated rispetto target solution, da

(0.30 color(red)(cancel(color(black)("M"))))/(0.10color(red)(cancel(color(black)("M")))) = 3

Questo ti dice che il volume of the target solution must be 3 times greater than the volume of the initial solution.

That is the case because when you dilute a solution, you diminuire la sua concentrazione di crescente its volume while keeping the number of moles of soluto constant. This implies that when the concentration of a solution diminuisce by a factor, which is usually called fattore di diluizione, "DF", upon dilution, the volume of the diluted solution aumenta by the same factor "DF".

color(blue)(|bar(ul(color(white)(a/a)"DF" = V_"final"/V_"initial" = c_"initial"/c_"final"color(white)(a/a)|)))

Quindi hai

V_"final" = 3 xx "250 mL" = color(green)(|bar(ul(color(white)(a/a)color(black)("750 mL")color(white)(a/a)|)))

La risposta è arrotondata a due sig fichi.

So, you can decrease the concentration of "250 mL" of sodium hydroxide solution from "0.30 M" a "0.10 M" by adding enough water to get its final volume to "750 mL".