# Come consideri  x ^ 2 + 16x + 64 ?

(x+8)^2

#### Spiegazione:

x^2+16x+64" is a "color(blue)"perfect square"

"that is "(x+a)^2=x^2+2ax+a^2

"compare the coefficients of the x-term"

rArr2a=16rArra=8

rarrx^2+16a+64=(x+8)^2