Come si scrive il numero complesso in forma trigonometrica # 6-7i #?

Risposta:

#sqrt85(cos(0.862)-isin(0.862))#

Spiegazione:

#"to convert from"color(blue)" complex to trig. form"#

#"that is "x+yitor(costheta+isintheta)" using"#

#•color(white)(x)r=sqrt(x^2+y^2)#

#•color(white)(x)theta=tan^-1(y/x)color(white)(x);-pi< theta <=pi#

#"here "x=6" and "y=-7#

#rArrr=sqrt(6^2+(-7)^2)=sqrt85#

#6-7i" is in the fourth quadrant so we must ensure that "theta#
#"is in the fourth quadrant"#

#rArrtheta=tan^-1(7/6)=0.862larrcolor(red)" related acute angle"#

#rArrtheta=-0.862larrcolor(red)" in fourth quadrant"#

#rArr6-7i=sqrt85(cos(-0.862)+isin(-0.862))#

#[cos(-0.862=cos(0.862);sin(-0.862)=-sin(0.862)]#

#rArr6-7i=sqrt85(cos(0.862)-isin(0.862))#

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